A small country emits 114,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by 0.5% per year for the next 5 years. In the first year of the agreement, the country will keep its emissions at 114,000 kilotons and the emissions will decrease 0.5% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 5 year period, to the nearest whole number? Answer:

Question

A small country emits 114,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by  0.5% per year for the next 5 years. In the first year of the agreement, the country will keep its emissions at 114,000 kilotons and the emissions will decrease  0.5% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 5 year period, to the nearest whole number? Answer:

Bytelearn · Accepted Answer

Set up formula: Understand the problem and set up the formula for the first year. In the first year, the country will emit the same amount of carbon dioxide as it does currently, which is 114,000 kilotons.Calculate second year: Calculate the emissions for the second year. To find the emissions for the second year, we need to decrease the first year's emissions by 0.5%. This is calculated as follows: Emissions for second year = Emissions for first year - (0.5% of Emissions for first year) Emissions for second year = 114,000 kilotons - (0.5/100 * 114,000 kilotons) Emissions for second year = 114,000 kilotons - 570 kilotons Emissions for second year = 113,430 kilotonsCalculate third year: Calculate the emissions for the third year. We apply the same 0.5% reduction to the emissions of the second year: Emissions for third year = Emissions for second year - (0.5% of Emissions for second year) Emissions for third year = 113,430 kilotons - (0.5/100 * 113,430 kilotons) Emissions for third year = 113,430 kilotons - 567.15 kilotons Emissions for third year ≈ 112,862.85 kilotonsCalculate fourth year: Calculate the emissions for the fourth year. Again, we apply the 0.5% reduction to the emissions of the third year: Emissions for fourth year = Emissions for third year - (0.5% of Emissions for third year) Emissions for fourth year = 112,862.85 kilotons - (0.5/100 * 112,862.85 kilotons) Emissions for fourth year ≈ 112,862.85 kilotons - 564.31425 kilotons Emissions for fourth year ≈ 112,298.54 kilotonsCalculate fifth year: Calculate the emissions for the fifth year. We apply the 0.5% reduction to the emissions of the fourth year: Emissions for fifth year = Emissions for fourth year - (0.5% of Emissions for fourth year) Emissions for fifth year = 112,298.54 kilotons - (0.5/100 * 112,298.54 kilotons) Emissions for fifth year ≈ 112,298.54 kilotons - 561.4927 kilotons Emissions for fifth year ≈ 111,737.05 kilotonsCalculate total emissions: Add up the emissions for all five years to get the total emissions. Total emissions = Emissions for first year + Emissions for second year + Emissions for third year + Emissions for fourth year + Emissions for fifth year Total emissions ≈ 114,000 + 113,430 + 112,862.85 + 112,298.54 + 111,737.05 kilotons Total emissions ≈ 564,328.44 kilotonsRound total emissions: Round the total emissions to the nearest whole number. Total emissions ≈ 564,328 kilotons

Full solution

More problems from Exponential growth and decay: word problems

Related topics