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A rental car company charges $50 plus 45 cents for each mile driven.
Part1. Find an equation that could be used to model the total cost, C, of the rental where
m represents the miles driven.
C = ◻
Part 2. The total cost of driving 325 miles is;
$ = ◻

A rental car company charges $\$ 50$ plus $45$ cents for each mile driven. $\newline$ Part $1$ . Find an equation that could be used to model the total cost, $\mathrm{C}$ , of the rental where $m$ represents the miles driven. $\newline$ $C = \square$ $\newline$ Part $2$ . The total cost of driving $325$ miles is; $\newline$ $\$ \square$

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Write a linear function: word problems

Full solution

Q. A rental car company charges

\$ 50

plus

45

cents for each mile driven.

\newline

Part

1

. Find an equation that could be used to model the total cost,

\mathrm{C}

, of the rental where

m

represents the miles driven.

\newline

C = \square

\newline

Part

2

. The total cost of driving

325

miles is;

\newline

\$ \square

Base Charge: The base charge is $\$50$ , no matter how many miles are driven.
Charge per Mile: The charge per mile is $45$ cents, or $\$0.45$ .
Total Cost Model: The total cost $C$ can be modeled by the equation $C = \text{base charge} + (\text{charge per mile} \times \text{number of miles})$ .
Cost Calculation: So the equation is $C = 50 + 0.45m$ , where $m$ is the number of miles driven.
Plug in Miles: Now we need to calculate the total cost for driving $325$ miles.
Calculate Mile Cost: Plug $325$ into the equation for $m$ : $C = 50 + 0.45(325)$ .
Add Base Charge: Calculate the cost for the miles: $\(0\).\(45\) \times \(325\) = \$(\(146\).\(25\)).
Add Base Charge: Calculate the cost for the miles: \(0.45 \times 325 = \$(146.25)\). Add the base charge to the cost for miles: \(\$50 + \$(146.25) = \$(196.25)\).

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