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A radioactive compound with mass 180 grams decays at a rate of 
4% per hour. Which equation represents how many grams of the compound will remain after 8 hours?

C=180(0.96)^(8)

C=180(1-0.04)(1-0.04)(1-0.04)

C=180(1+0.04)^(8)

C=180(1-0.4)^(8)

A radioactive compound with mass 180180 grams decays at a rate of 4% 4 \% per hour. Which equation represents how many grams of the compound will remain after 88 hours?\newlineC=180(0.96)8 C=180(0.96)^{8} \newlineC=180(10.04)(10.04)(10.04) C=180(1-0.04)(1-0.04)(1-0.04) \newlineC=180(1+0.04)8 C=180(1+0.04)^{8} \newlineC=180(10.4)8 C=180(1-0.4)^{8}

Full solution

Q. A radioactive compound with mass 180180 grams decays at a rate of 4% 4 \% per hour. Which equation represents how many grams of the compound will remain after 88 hours?\newlineC=180(0.96)8 C=180(0.96)^{8} \newlineC=180(10.04)(10.04)(10.04) C=180(1-0.04)(1-0.04)(1-0.04) \newlineC=180(1+0.04)8 C=180(1+0.04)^{8} \newlineC=180(10.4)8 C=180(1-0.4)^{8}
  1. Understand the problem: Understand the problem.\newlineWe need to find the equation that correctly represents the decay of a radioactive compound that starts with a mass of 180180 grams and decays at a rate of 4%4\% per hour over a period of 88 hours.
  2. Identify the correct decay formula: Identify the correct decay formula.\newlineThe general formula for exponential decay is given by C=C0×(1r)tC = C_0 \times (1 - r)^t, where C0C_0 is the initial amount, rr is the decay rate per unit time, and tt is the time.
  3. Substitute values into formula: Substitute the given values into the decay formula. \newlineC0=180C_0 = 180 grams (initial amount), r=4%r = 4\% per hour (decay rate), and t=8t = 8 hours (time).\newlineConvert the percentage decay rate to a decimal: 4%=0.044\% = 0.04.
  4. Write equation with values: Write the equation using the values from Step 33. C=180×(10.04)8C = 180 \times (1 - 0.04)^8
  5. Check for matching equation: Check the given options to see which one matches the equation from Step 44.\newlineThe correct equation is C=180×(10.04)8C = 180 \times (1 - 0.04)^8, which simplifies to C=180×(0.96)8C = 180 \times (0.96)^8.
  6. Verify other options: Verify that none of the other options match the correct equation.\newlineOption B: C=180×(10.04)(10.04)(10.04)C = 180 \times (1 - 0.04)(1 - 0.04)(1 - 0.04) is incorrect because it only accounts for three hours of decay, not eight.\newlineOption C: C=180×(1+0.04)8C = 180 \times (1 + 0.04)^8 is incorrect because it suggests growth, not decay.\newlineOption D: C=180×(10.4)8C = 180 \times (1 - 0.4)^8 is incorrect because the decay rate is 4%4\%, not 40%40\%.

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