Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A principal amount of $10,000\$10,000 is invested in a continuously compounded account. After 1515 years, the investment grows to $25,000\$25,000. Find the annual interest rate. Round your answer to the nearest two decimal places in percentage form. Use the formula A=PertA = Pe^{rt}, where AA is the balance (final amount), PP is the principal (starting amount), ee is the base of natural logarithms (2.71828\approx 2.71828), rr is the interest rate expressed as a decimal, and tt is the time in years.

Full solution

Q. A principal amount of $10,000\$10,000 is invested in a continuously compounded account. After 1515 years, the investment grows to $25,000\$25,000. Find the annual interest rate. Round your answer to the nearest two decimal places in percentage form. Use the formula A=PertA = Pe^{rt}, where AA is the balance (final amount), PP is the principal (starting amount), ee is the base of natural logarithms (2.71828\approx 2.71828), rr is the interest rate expressed as a decimal, and tt is the time in years.
  1. Identify values PP, AA, tt: Identify the values for PP, AA, and tt. P=10,000P = 10,000 A=25,000A = 25,000 t=15t = 15
  2. Use formula A=PertA = Pe^{rt}: Use the formula A=PertA = Pe^{rt}. 25,000=10,000imese15r25,000 = 10,000 imes e^{15r}
  3. Divide both sides: Divide both sides by 10,00010,000. 2.5=e15r2.5 = e^{15r}
  4. Take natural logarithm: Take the natural logarithm (ln) of both sides. ln(2.5)=15r\ln(2.5) = 15r
  5. Solve for rr: Solve for rr. r=ln(2.5)15r = \frac{\ln(2.5)}{15}
  6. Calculate ln(2.5) \ln(2.5) : Calculate ln(2.5) \ln(2.5) . ln(2.5)0.9162907 \ln(2.5) \approx 0.9162907
  7. Divide by 1515: Divide by 1515.
    r0.916290715r \approx \frac{0.9162907}{15}
    r0.061086r \approx 0.061086
  8. Convert rr to percentage: Convert rr to a percentage and round to two decimal places. r0.061086×100r \approx 0.061086 \times 100 r6.11%r \approx 6.11\%

More problems from Continuously compounded interest: word problems