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A pizza shop has available toppings of peppers, sausage, pepperoni, bacon, and mushrooms. How many different ways can a pizza be made with 2 toppings?
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A pizza shop has available toppings of peppers, sausage, pepperoni, bacon, and mushrooms. How many different ways can a pizza be made with 22 toppings?\newlineAnswer:

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Q. A pizza shop has available toppings of peppers, sausage, pepperoni, bacon, and mushrooms. How many different ways can a pizza be made with 22 toppings?\newlineAnswer:
  1. Given Toppings Selection: We are given 55 different toppings to choose from and we want to know the number of different pizzas we can make with exactly 22 toppings. This is a combination problem because the order in which we select the toppings does not matter. The formula for combinations is C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n - k)!}, where nn is the total number of items to choose from, kk is the number of items to choose, n!n! is the factorial of nn, and k!k! is the factorial of kk.
  2. Calculate Total Toppings Factorial: First, we calculate the factorial of the total number of toppings nn, which is 55. The factorial of a number is the product of all positive integers up to that number. So, 5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120.
  3. Calculate Toppings Wanted Factorial: Next, we calculate the factorial of the number of toppings we want on the pizza kk, which is 22. So, 2!=2×1=22! = 2 \times 1 = 2.
  4. Calculate Remaining Toppings Factorial: We also need to calculate the factorial of the difference between the total number of toppings and the number of toppings we want on the pizza nkn - k. Since nn is 55 and kk is 22, nk=52=3n - k = 5 - 2 = 3. So, 3!=3×2×1=63! = 3 \times 2 \times 1 = 6.
  5. Use Combination Formula: Now we can use the combination formula to find the number of different pizzas that can be made with 22 toppings. We plug in our values into the formula C(5,2)=5!(2!(52)!)C(5, 2) = \frac{5!}{(2!(5 - 2)!)}.
  6. Substitute Factorial Values: Substitute the factorial values we calculated into the formula: C(5,2)=1202×6C(5, 2) = \frac{120}{2 \times 6}.
  7. Perform Calculations: Perform the calculations: C(5,2)=1202×6=12012=10C(5, 2) = \frac{120}{2 \times 6} = \frac{120}{12} = 10.

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