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A piece of paper is to display 150 square inches of text. If there are to be one-inch margins on the sides and the top and a two-inch margin at the bottom, what are the dimensions of the smallest piece of paper that can be used?
Choose 1 answer:
(A) 
6''×25''
(B) 
10''×15''
(C) 
12'×18''
(D) 
15||×18||
(E) None of these

A piece of paper is to display 150150 square inches of text. If there are to be one-inch margins on the sides and the top and a two-inch margin at the bottom, what are the dimensions of the smallest piece of paper that can be used?\newlineChoose 11 answer:\newline(A) 6×25 6 \prime \prime \times 25 \prime \prime \newline(B) 10×15 10 \prime \prime \times 15 \prime \prime \newline(C) 12×18 12 \prime \prime \times 18 \prime \prime \newline(D) 15×18 15 \prime \prime \times 18 \prime \prime\newline(E) None of these

Full solution

Q. A piece of paper is to display 150150 square inches of text. If there are to be one-inch margins on the sides and the top and a two-inch margin at the bottom, what are the dimensions of the smallest piece of paper that can be used?\newlineChoose 11 answer:\newline(A) 6×25 6 \prime \prime \times 25 \prime \prime \newline(B) 10×15 10 \prime \prime \times 15 \prime \prime \newline(C) 12×18 12 \prime \prime \times 18 \prime \prime \newline(D) 15×18 15 \prime \prime \times 18 \prime \prime\newline(E) None of these
  1. Define Variables: Let's call the width of the paper ww inches and the height hh inches. The text area is 150150 square inches.
  2. Calculate Text Area: The margins reduce the width by 22 inches (11 inch on each side) and the height by 33 inches (11 inch on the top and 22 inches at the bottom).
  3. Solve Equation: So, the text area can be represented by (w2)(h3)=150(w - 2)(h - 3) = 150.
  4. Evaluate Options: We need to find the smallest ww and hh that satisfy this equation. Let's start by trying the options given.
  5. Option A: Option (A): If w=6w = 6 and h=25h = 25, then (62)(253)=4×22=88(6 - 2)(25 - 3) = 4 \times 22 = 88, which is not equal to 150150.
  6. Option B: Option (B): If w=10w = 10 and h=15h = 15, then (102)(153)=8×12=96(10 - 2)(15 - 3) = 8 \times 12 = 96, which is not equal to 150150.
  7. Option C: Option (C): If w=12w = 12 and h=18h = 18, then (122)(183)=10×15=150(12 - 2)(18 - 3) = 10 \times 15 = 150, which is equal to 150150.
  8. Final Dimensions: So, the dimensions of the smallest piece of paper that can be used are 1212 inches by 1818 inches.

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