A particle moves along the x-axis with velocityv(t)=ln(t2+5t+1). What is the particle's displacement between the times t=1 and t=5 ?Use a graphing calculator and round your answer to three decimal places.
Q. A particle moves along the x-axis with velocityv(t)=ln(t2+5t+1). What is the particle's displacement between the times t=1 and t=5 ?Use a graphing calculator and round your answer to three decimal places.
Integrate Velocity Function: To find the displacement, we need to integrate the velocity function from t=1 to t=5.
Set Up Integral: Set up the integral: ∫15ln(t2+5t+1)dt.
Evaluate Integral: Use a graphing calculator to evaluate the integral.
Calculate Displacement: After using the calculator, we get the approximate value of the integral, which is the displacement.
Approximate Displacement: The calculator shows the displacement is approximately 9.154.
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