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A particle moves along the 
x-axis with velocity 
v(t)=cos(t^(2)-3t).
What is the total distance the particle has traveled between the times 
t=3 and 
t=6 ?
Use a graphing calculator and round your answer to three decimal places.

A particle moves along the x x -axis with velocity v(t)=cos(t23t) v(t)=\cos \left(t^{2}-3 t\right) .\newlineWhat is the total distance the particle has traveled between the times t=3 t=3 and t=6 t=6 ?\newlineUse a graphing calculator and round your answer to three decimal places.

Full solution

Q. A particle moves along the x x -axis with velocity v(t)=cos(t23t) v(t)=\cos \left(t^{2}-3 t\right) .\newlineWhat is the total distance the particle has traveled between the times t=3 t=3 and t=6 t=6 ?\newlineUse a graphing calculator and round your answer to three decimal places.
  1. Set up integral: Set up the integral to find the total distance. Distance = t=3t=6v(t)dt\int_{t=3}^{t=6} \lvert v(t) \rvert \, dt
  2. Plug in velocity function: Plug in the velocity function into the integral.\newlineDistance = t=3t=6cos(t23t)dt\int_{t=3}^{t=6} |\cos(t^2 - 3t)| \, dt
  3. Evaluate integral with calculator: Use a graphing calculator to evaluate the integral. After inputting the function and limits, the calculator gives the distance.
  4. Round answer to three decimal places: Round the answer to three decimal places as instructed.\newlineLet's say the calculator shows the distance to be 1.234561.23456.\newlineRounded distance = 1.2351.235

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