A particle moves along the x-axis such that at any time t≥0 its position is x(t), its velocity is v(t), and its acceleration is a(t). You are given:x(2)=1 and v(2)=7Which of the following expression gives the position of the particle when t=0 ?1+∫20v(t)dt1+∫02v(t)dt2+∫20v(t)dt2+∫02v(t)dt
Q. A particle moves along the x-axis such that at any time t≥0 its position is x(t), its velocity is v(t), and its acceleration is a(t). You are given:x(2)=1 and v(2)=7Which of the following expression gives the position of the particle when t=0 ?1+∫20v(t)dt1+∫02v(t)dt2+∫20v(t)dt2+∫02v(t)dt
Integrate Velocity Function: To find the position of the particle at time t=0, we need to integrate the velocity function from time t=0 to t=2, since we know the position at t=2 and the velocity at t=2. The integral of the velocity function will give us the change in position from t=0 to t=2.
Calculate Position at t=0: We are given x(2)=1 and v(2)=7. To find x(0), we need to subtract the change in position from t=2 to t=0 from x(2). This change in position is given by the integral of the velocity function from t=0 to t=2, not from t=2 to t=0. Therefore, we should use the integral with limits from x(2)=11 to x(2)=12.
Find Correct Expression: The correct expression for the position of the particle at t=0 is therefore: x(0)=x(2)−∫t=0t=2v(t)dt Since x(2)=1, the expression becomes: x(0)=1−∫t=0t=2v(t)dt
Choose Correct Option: The correct choice from the given options that represents this expression is: 1+∫t=0t=2v(t)dtThis is because the integral of velocity from t=0 to t=2 gives the change in position during this time interval, which when added to the position at t=2, gives the position at t=0.
Final Answer: The correct answer is therefore the second option: 1+∫t=0t=2v(t)dt
More problems from Relate position, velocity, speed, and acceleration using derivatives