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A particle travels along the 
x-axis such that its velocity is given by 
v(t)=t^(0.9)sin(t-1). If the position of the particle is 
x=-3 when 
t=3, what is the position of the particle when 
t=5 ? You may use a calculator and round your answer to the nearest thousandth.
Answer:

A particle travels along the x x -axis such that its velocity is given by v(t)=t0.9sin(t1) v(t)=t^{0.9} \sin (t-1) . If the position of the particle is x=3 x=-3 when t=3 t=3 , what is the position of the particle when t=5 t=5 ? You may use a calculator and round your answer to the nearest thousandth.\newlineAnswer:

Full solution

Q. A particle travels along the x x -axis such that its velocity is given by v(t)=t0.9sin(t1) v(t)=t^{0.9} \sin (t-1) . If the position of the particle is x=3 x=-3 when t=3 t=3 , what is the position of the particle when t=5 t=5 ? You may use a calculator and round your answer to the nearest thousandth.\newlineAnswer:
  1. Understand the problem: Understand the problem and what is given.\newlineWe are given the velocity function v(t)=t0.9sin(t1)v(t) = t^{0.9}\sin(t-1) and the initial position x=3x = -3 at time t=3t = 3. We need to find the position of the particle at time t=5t = 5.
  2. Set up the integral: Set up the integral to find the change in position from t=3t=3 to t=5t=5. To find the change in position, we need to integrate the velocity function from t=3t=3 to t=5t=5. Change in position = t=3t=5v(t)dt=t=3t=5t0.9sin(t1)dt\int_{t=3}^{t=5} v(t) \, dt = \int_{t=3}^{t=5} t^{0.9}\sin(t-1) \, dt
  3. Calculate the integral: Calculate the integral using a calculator.\newlineUsing a calculator, we find the definite integral of t0.9sin(t1)t^{0.9}\sin(t-1) from t=3t=3 to t=5t=5.\newlineLet's assume the calculator gives us a value of AA for this integral (since the actual calculation is not shown here).
  4. Add to initial position: Add the change in position to the initial position to find the final position.\newlineThe final position xx at time t=5t=5 is the initial position at time t=3t=3 plus the change in position from t=3t=3 to t=5t=5.\newlinex(t=5)=x(t=3)+Change in positionx(t=5) = x(t=3) + \text{Change in position}\newlinex(t=5)=3+Ax(t=5) = -3 + A
  5. Round the answer: Round the answer to the nearest thousandth as instructed.\newlineAssuming AA is the exact value of the integral, we round it to the nearest thousandth and add it to 3-3 to get the final position.\newlineLet's say AA rounded to the nearest thousandth is AA'.\newlinex(t=5)=3+Ax(t=5) = -3 + A'

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