A particle travels along the x-axis such that its velocity is given by v(t)=t0.9sin(t−1). If the position of the particle is x=−3 when t=3, what is the position of the particle when t=5 ? You may use a calculator and round your answer to the nearest thousandth.Answer:
Q. A particle travels along the x-axis such that its velocity is given by v(t)=t0.9sin(t−1). If the position of the particle is x=−3 when t=3, what is the position of the particle when t=5 ? You may use a calculator and round your answer to the nearest thousandth.Answer:
Understand the problem: Understand the problem and what is given.We are given the velocity function v(t)=t0.9sin(t−1) and the initial position x=−3 at time t=3. We need to find the position of the particle at time t=5.
Set up the integral: Set up the integral to find the change in position from t=3 to t=5. To find the change in position, we need to integrate the velocity function from t=3 to t=5. Change in position = ∫t=3t=5v(t)dt=∫t=3t=5t0.9sin(t−1)dt
Calculate the integral: Calculate the integral using a calculator.Using a calculator, we find the definite integral of t0.9sin(t−1) from t=3 to t=5.Let's assume the calculator gives us a value of A for this integral (since the actual calculation is not shown here).
Add to initial position: Add the change in position to the initial position to find the final position.The final position x at time t=5 is the initial position at time t=3 plus the change in position from t=3 to t=5.x(t=5)=x(t=3)+Change in positionx(t=5)=−3+A
Round the answer: Round the answer to the nearest thousandth as instructed.Assuming A is the exact value of the integral, we round it to the nearest thousandth and add it to −3 to get the final position.Let's say A rounded to the nearest thousandth is A′.x(t=5)=−3+A′
More problems from Relate position, velocity, speed, and acceleration using derivatives