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A particle moves along the $x$-axis such that at any time $t \geq 0$ its position is $x(t)$, its velocity is $v(t)$, and its acceleration is $a(t)$. You are given:$\newline$$$x(1)=8 \quad \text { and } \quad v(1)=4$$$\newline$Which of the following expression gives the position of the particle when $t=8 ?$$\newline$$1+\int_{8}^{8} v(t) d t$$\newline$$1+\int_{8}^{8} v(t) d t$$\newline$$8+\int_{1}^{8} v(t) d t$$\newline$$8+\int_{8}^{1} v(t) d t$