Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A particle moves along the 
x-axis such that at any time 
t >= 0 its position is 
x(t), its velocity is 
v(t), and its acceleration is 
a(t). You are given:

x(1)=7quad" and "quad v(1)=4
Which of the following expression gives the position of the particle when 
t=9?

7+int_(1)^(9)v(t)dt

1+int_(7)^(9)v(t)dt

7+int_(9)^(1)v(t)dt

1+int_(9)^(7)v(t)dt

A particle moves along the x x -axis such that at any time t0 t \geq 0 its position is x(t) x(t) , its velocity is v(t) v(t) , and its acceleration is a(t) a(t) . You are given:\newlinex(1)=7 and v(1)=4 x(1)=7 \quad \text { and } \quad v(1)=4 \newlineWhich of the following expression gives the position of the particle when t=9? t=9 ? \newline7+19v(t)dt 7+\int_{1}^{9} v(t) d t \newline1+79v(t)dt 1+\int_{7}^{9} v(t) d t \newline7+91v(t)dt 7+\int_{9}^{1} v(t) d t \newline1+97v(t)dt 1+\int_{9}^{7} v(t) d t

Full solution

Q. A particle moves along the x x -axis such that at any time t0 t \geq 0 its position is x(t) x(t) , its velocity is v(t) v(t) , and its acceleration is a(t) a(t) . You are given:\newlinex(1)=7 and v(1)=4 x(1)=7 \quad \text { and } \quad v(1)=4 \newlineWhich of the following expression gives the position of the particle when t=9? t=9 ? \newline7+19v(t)dt 7+\int_{1}^{9} v(t) d t \newline1+79v(t)dt 1+\int_{7}^{9} v(t) d t \newline7+91v(t)dt 7+\int_{9}^{1} v(t) d t \newline1+97v(t)dt 1+\int_{9}^{7} v(t) d t
  1. Understand Question Prompt: The question prompt asks us to find the expression that gives the position of the particle when t=9t=9, given that x(1)=7x(1)=7 and v(1)=4v(1)=4. We know that the position of a particle at any time tt can be found by taking the initial position and adding the integral of the velocity function from the initial time to the time tt.
  2. Initial Position and Value: The correct expression for the position of the particle at time t=9t=9 should start with the initial position at time t=1t=1, which is given as x(1)=7x(1)=7. This means that the initial value in our expression should be 77.
  3. Calculate Integral of Velocity: Next, we need to add the integral of the velocity function v(t)v(t) from the initial time t=1t=1 to the final time t=9t=9. This is represented mathematically as the integral from 11 to 99 of v(t)dtv(t) \, dt. This integral will give us the change in position from time t=1t=1 to time t=9t=9.
  4. Final Expression for Position: Therefore, the correct expression that gives the position of the particle when t=9t=9 is the initial position plus the integral of the velocity function from time t=1t=1 to t=9t=9. This is represented as:\newline7+19v(t)dt7 + \int_{1}^{9} v(t) \, dt.
  5. Match with Provided Options: Looking at the options provided, the expression that matches our derived expression is: 7+19v(t)dt7 + \int_{1}^{9} v(t) \, dt.

More problems from Relate position, velocity, speed, and acceleration using derivatives