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A particle moves along the $x$-axis such that at any time $t \geq 0$ its position is $x(t)$, its velocity is $v(t)$, and its acceleration is $a(t)$. You are given:$\newline$$$x(2)=4 \quad \text { and } \quad v(2)=6$$$\newline$Which of the following expression gives the velocity of the particle when $t=9 ?$$\newline$$6+\int_{9}^{2} a(t) d t$$\newline$$6+\int_{9}^{2} v(t) d t$$\newline$$6+\int_{2}^{9} a(t) d t$$\newline$$6+\int_{2}^{9} v(t) d t$