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A particle moves along the 
x-axis so that at time 
t >= 0 its velocity is given by 
v(t)=-2t+5. Determine the acceleration of the particle at 
t=6.
Answer:

A particle moves along the x x -axis so that at time t0 t \geq 0 its velocity is given by v(t)=2t+5 v(t)=-2 t+5 . Determine the acceleration of the particle at t=6 t=6 .\newlineAnswer:

Full solution

Q. A particle moves along the x x -axis so that at time t0 t \geq 0 its velocity is given by v(t)=2t+5 v(t)=-2 t+5 . Determine the acceleration of the particle at t=6 t=6 .\newlineAnswer:
  1. Identify Relationship: Identify the relationship between velocity and acceleration. Acceleration is the derivative of velocity with respect to time.
  2. Differentiate Velocity Function: Differentiate the velocity function v(t)=2t+5v(t) = -2t + 5 to find the acceleration function a(t)a(t). The derivative of 2t-2t with respect to tt is 2-2, and the derivative of a constant 55 is 00. So, a(t)=2a(t) = -2.
  3. Evaluate Acceleration at t=6t=6: Evaluate the acceleration function at t=6t=6. Since the acceleration function a(t)a(t) is constant and equal to 2-2, the acceleration at t=6t=6 is also 2-2.

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