Q. A particle moves along the x-axis so that at time t≥0 its velocity is given by v(t)=−2t+5. Determine the acceleration of the particle at t=6.Answer:
Identify Relationship: Identify the relationship between velocity and acceleration. Acceleration is the derivative of velocity with respect to time.
Differentiate Velocity Function: Differentiate the velocity function v(t)=−2t+5 to find the acceleration function a(t). The derivative of −2t with respect to t is −2, and the derivative of a constant 5 is 0. So, a(t)=−2.
Evaluate Acceleration at t=6: Evaluate the acceleration function at t=6. Since the acceleration function a(t) is constant and equal to −2, the acceleration at t=6 is also −2.
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