Q. A particle moves along the x-axis so that at time t≥0 its velocity is given by v(t)=3t2−28t+25. Determine the speed of the particle at t=9.Answer:
Identify Given Velocity Function: Identify the given velocity function and the time at which we need to find the speed.The velocity function is v(t)=3t2−28t+25, and we need to find the speed at t=9.
Plug in Value of t: Plug the value of t into the velocity function to find the velocity at t=9. v(9)=3(9)2−28(9)+25
Calculate Velocity at t=9: Calculate the velocity at t=9.v(9)=3(81)−28(9)+25v(9)=243−252+25
Finish Velocity Calculation: Finish the calculation of the velocity at t=9.v(9)=243−252+25v(9)=−9+25v(9)=16
Calculate Speed at t=9: Since speed is the absolute value of velocity, calculate the speed at t=9. Speed at t=9 = ∣v(9)∣ Speed at t=9 = ∣16∣
Conclude Final Speed: Conclude with the final value of the speed at t=9.Speed at t=9 = 16 (since 16 is already positive, its absolute value is also 16)
More problems from Relate position, velocity, speed, and acceleration using derivatives