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A particle moves along the 
x-axis so that at time 
t >= 0 its velocity is given by 
v(t)=3t^(2)-28 t+25. Determine the speed of the particle at 
t=9.
Answer:

A particle moves along the x x -axis so that at time t0 t \geq 0 its velocity is given by v(t)=3t228t+25 v(t)=3 t^{2}-28 t+25 . Determine the speed of the particle at t=9 t=9 .\newlineAnswer:

Full solution

Q. A particle moves along the x x -axis so that at time t0 t \geq 0 its velocity is given by v(t)=3t228t+25 v(t)=3 t^{2}-28 t+25 . Determine the speed of the particle at t=9 t=9 .\newlineAnswer:
  1. Identify Given Velocity Function: Identify the given velocity function and the time at which we need to find the speed.\newlineThe velocity function is v(t)=3t228t+25v(t)=3t^{2}-28t+25, and we need to find the speed at t=9t=9.
  2. Plug in Value of t: Plug the value of tt into the velocity function to find the velocity at t=9t=9. \newlinev(9)=3(9)228(9)+25v(9)=3(9)^{2}-28(9)+25
  3. Calculate Velocity at t=9t=9: Calculate the velocity at t=9t=9.v(9)=3(81)28(9)+25v(9)=3(81)-28(9)+25v(9)=243252+25v(9)=243-252+25
  4. Finish Velocity Calculation: Finish the calculation of the velocity at t=9t=9.v(9)=243252+25v(9)=243-252+25v(9)=9+25v(9)=-9+25v(9)=16v(9)=16
  5. Calculate Speed at t=9t=9: Since speed is the absolute value of velocity, calculate the speed at t=9t=9.
    Speed at t=9t=9 = v(9)|v(9)|
    Speed at t=9t=9 = 16|16|
  6. Conclude Final Speed: Conclude with the final value of the speed at t=9t=9.\newlineSpeed at t=9t=9 = 1616 (since 1616 is already positive, its absolute value is also 1616)

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