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A motorboat left a harbor and traveled at an average speed of 15mph15\,\text{mph} toward an island. The average speed on its return trip was 10mph10\,\text{mph}. How far was the island from the harbor if the total trip took 55 hours?

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Q. A motorboat left a harbor and traveled at an average speed of 15mph15\,\text{mph} toward an island. The average speed on its return trip was 10mph10\,\text{mph}. How far was the island from the harbor if the total trip took 55 hours?
  1. Set up equation: Let's denote the distance to the island as d d miles. The time to travel to the island is d15 \frac{d}{15} hours, and the time for the return trip is d10 \frac{d}{10} hours. The total time for both trips is 55 hours. Set up the equation:\newlined15+d10=5 \frac{d}{15} + \frac{d}{10} = 5
  2. Find common denominator: To solve for d d , find a common denominator for the fractions, which is 3030. Rewrite the equation:\newline2d30+3d30=5 \frac{2d}{30} + \frac{3d}{30} = 5
  3. Combine terms: Combine the terms on the left side:\newline5d30=5 \frac{5d}{30} = 5
  4. Simplify equation: Simplify the equation by multiplying both sides by 3030:\newline5d=150 5d = 150
  5. Divide to solve: Divide both sides by 55 to solve for d d :\newlined=30 d = 30

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