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A line with a slope of 16\frac{1}{6} passes through the point (8,−4)(8,-4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Q. A line with a slope of 16\frac{1}{6} passes through the point (8,−4)(8,-4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  2. Substitute Values: We have:\newlinePoint: (8,−4)(8, -4)\newlineSlope: 16\frac{1}{6}\newlineWhat is the point-slope form of the line?\newlineSubstitute 16\frac{1}{6} for mm, 88 for x1x_1, and −4-4 for y1y_1 in the point-slope form.\newliney−(−4)=(16)(x−8)y - (-4) = \left(\frac{1}{6}\right)(x - 8)
  3. Simplify Equation: Simplify the equation by removing the parentheses around −4-4.\newliney+4=16(x−8)y + 4 = \frac{1}{6}(x - 8)\newlineThis is the equation of the line in point-slope form.

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