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A line with a slope of −16-\frac{1}{6} passes through the point (8,6)(8,6). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−______=______(x−______)y - \_\_\_\_\_\_ = \_\_\_\_\_\_(x - \_\_\_\_\_\_)

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Q. A line with a slope of −16-\frac{1}{6} passes through the point (8,6)(8,6). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−______=______(x−______)y - \_\_\_\_\_\_ = \_\_\_\_\_\_(x - \_\_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  2. Given Point and Slope: We have:\newlinePoint: (8,6)(8, 6)\newlineSlope: −16-\frac{1}{6}\newlineWhat is the point-slope form of the line?\newlineSubstitute −16-\frac{1}{6} for mm, 88 for x1x_1, and 66 for y1y_1 in point-slope form.\newliney−6=(−16)(x−8)y - 6 = \left(-\frac{1}{6}\right)(x - 8)

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