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A line with a slope of 14\frac{1}{4} passes through the point (−8,−8)(-8,-8). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line with a slope of 14\frac{1}{4} passes through the point (−8,−8)(-8,-8). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify point-slope form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute slope and point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=14m = \frac{1}{4} and the point (−8,−8)(-8, -8). Substituting these values into the point-slope form, we get y−(−8)=(14)(x−(−8))y - (-8) = \left(\frac{1}{4}\right)(x - (-8)).
  3. Simplify the equation: Simplify the equation.\newlineSimplifying the equation, we get y+8=(14)(x+8)y + 8 = \left(\frac{1}{4}\right)(x + 8). This is the equation of the line in point-slope form.

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