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A line with a slope of −12-\frac{1}{2} passes through the point (−3,−6)(-3,-6). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line with a slope of −12-\frac{1}{2} passes through the point (−3,−6)(-3,-6). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe have the slope m=−12m = -\frac{1}{2} and the point (−3,−6)(-3, -6). Substituting these values into the point-slope form, we get:\newliney−(−6)=(−12)(x−(−3))y - (-6) = (-\frac{1}{2})(x - (-3))
  3. Simplify Equation: Simplify the equation.\newlineSimplify the equation by removing the parentheses and keeping the equation in point-slope form:\newliney+6=(−12)(x+3)y + 6 = \left(-\frac{1}{2}\right)(x + 3)

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