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A line that includes the point (−8,−5)(-8,-5) has a slope of −13-\frac{1}{3}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line that includes the point (−8,−5)(-8,-5) has a slope of −13-\frac{1}{3}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  2. Substitute Values: We have:\newlinePoint: (−8,−5)(-8, -5)\newlineSlope: −13-\frac{1}{3}\newlineWhat is the point-slope form of the line?\newlineSubstitute −13-\frac{1}{3} for mm, −8-8 for x1x_1, and −5-5 for y1y_1 in point-slope form.\newliney−(−5)=(−13)(x−(−8))y - (-5) = (-\frac{1}{3})(x - (-8))
  3. Simplify Equation: Simplify the equation by removing the double negatives.\newliney+5=(−13)(x+8)y + 5 = (-\frac{1}{3})(x + 8)

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