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A line that includes the point (−5,−6)(-5,-6) has a slope of 17\frac{1}{7}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line that includes the point (−5,−6)(-5,-6) has a slope of 17\frac{1}{7}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Given Point and Slope: Substitute the given point and slope into the point-slope form.\newlineWe are given the point (−5,−6)(-5, -6) and the slope 17\frac{1}{7}. Substituting these values into the point-slope form, we get:\newliney−(−6)=(17)(x−(−5))y - (-6) = \left(\frac{1}{7}\right)(x - (-5))\newlineSimplifying the equation, we have:\newliney+6=(17)(x+5)y + 6 = \left(\frac{1}{7}\right)(x + 5)
  3. Check for Errors: Check for any mathematical errors. We substituted the values correctly and simplified the equation without making any mistakes.

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