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A line that includes the point (−3,2)(-3,2) has a slope of −16-\frac{1}{6}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line that includes the point (−3,2)(-3,2) has a slope of −16-\frac{1}{6}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by the formula y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Given Point and Slope: Substitute the given point and slope into the point-slope form.\newlineWe are given the point (−3,2)(-3, 2) and the slope −16-\frac{1}{6}. Substituting these values into the point-slope form, we get:\newliney−2=(−16)(x−(−3))y - 2 = \left(-\frac{1}{6}\right)(x - (-3))\newlineSimplifying the equation, we have:\newliney−2=(−16)(x+3)y - 2 = \left(-\frac{1}{6}\right)(x + 3)

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