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A line that includes the point (2,6)(2,6) has a slope of 18\frac{1}{8}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line that includes the point (2,6)(2,6) has a slope of 18\frac{1}{8}. What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  2. Given Point and Slope: We have:\newlinePoint: (2,6)(2, 6)\newlineSlope: 18\frac{1}{8}\newlineWhat is the point-slope form of the line?\newlineSubstitute 18\frac{1}{8} for mm, 22 for x1x_1, and 66 for y1y_1 in point-slope form.\newliney−6=(18)(x−2)y - 6 = \left(\frac{1}{8}\right)(x - 2)

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