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A line has a slope of 19\frac{1}{9} and passes through the point (−7,−5)(-7,-5). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line has a slope of 19\frac{1}{9} and passes through the point (−7,−5)(-7,-5). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form is given by the equation y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe have the slope m=19m = \frac{1}{9} and the point (−7,−5)(-7, -5). Substituting these values into the point-slope form, we get y−(−5)=(19)(x−(−7))y - (-5) = \left(\frac{1}{9}\right)(x - (-7)).
  3. Simplify Equation: Simplify the equation.\newlineSimplifying the equation, we get y+5=(19)(x+7)y + 5 = \left(\frac{1}{9}\right)(x + 7). This is the equation of the line in point-slope form.

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