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A line has a slope of 17\frac{1}{7} and passes through the point (5,4)(-5,4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney_____=_____(x_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Q. A line has a slope of 17\frac{1}{7} and passes through the point (5,4)(-5,4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney_____=_____(x_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by the formula yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=17m = \frac{1}{7} and the point (5,4)(-5, 4). Substituting these values into the point-slope form, we get y4=(17)(x(5))y - 4 = \left(\frac{1}{7}\right)(x - (-5)).
  3. Simplify Equation: Simplify the equation.\newlineThe equation y4=(17)(x(5))y - 4 = (\frac{1}{7})(x - (-5)) simplifies to y4=(17)(x+5)y - 4 = (\frac{1}{7})(x + 5). There is no need to simplify further as the equation is already in point-slope form and the fractions are in their simplest form.

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