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A line has a slope of −17-\frac{1}{7} and passes through the point (−1,1)(-1,1). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line has a slope of −17-\frac{1}{7} and passes through the point (−1,1)(-1,1). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by the formula y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form. We are given the slope m=−17m = -\frac{1}{7} and the point (−1,1)(-1, 1). Substituting these values into the point-slope form, we get y−1=(−17)(x−(−1))y - 1 = \left(-\frac{1}{7}\right)(x - (-1)).
  3. Simplify Equation: Simplify the equation.\newlineSimplify the equation by distributing the slope and combining like terms if necessary. In this case, we have y−1=(−17)(x+1)y - 1 = \left(-\frac{1}{7}\right)(x + 1).

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