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A line has a slope of 16\frac{1}{6} and passes through the point (7,7)(7,7). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Q. A line has a slope of 16\frac{1}{6} and passes through the point (7,7)(7,7). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  2. Given Point and Slope: We have:\newlinePoint: (7,7)(7, 7)\newlineSlope: 16\frac{1}{6}\newlineWhat is the point-slope form of the line?\newlineSubstitute 16\frac{1}{6} for mm, 77 for x1x_1, and 77 for y1y_1 in point-slope form.\newliney−7=(16)(x−7)y - 7 = \left(\frac{1}{6}\right)(x - 7)

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