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A line has a slope of 15\frac{1}{5} and passes through the point (−5,3)(-5,3). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Q. A line has a slope of 15\frac{1}{5} and passes through the point (−5,3)(-5,3). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=15m = \frac{1}{5} and the point (−5,3)(-5, 3). Substituting these values into the point-slope form, we get:\newliney−3=(15)(x−(−5))y - 3 = \left(\frac{1}{5}\right)(x - (-5))
  3. Simplify Equation: Simplify the equation.\newlineThe equation simplifies to:\newliney−3=15(x+5)y - 3 = \frac{1}{5}(x + 5)\newlineThis is the equation of the line in point-slope form.

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