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A line has a slope of 13\frac{1}{3} and passes through the point (−10,−4)(-10,-4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})

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Q. A line has a slope of 13\frac{1}{3} and passes through the point (−10,−4)(-10,-4). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−‾=‾(x−‾)y - \underline{\quad} = \underline{\quad}(x - \underline{\quad})
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlinePoint-slope form is given by the equation y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe have the slope m=13m = \frac{1}{3} and the point (−10,−4)(-10, -4). Substituting these values into the point-slope form, we get:\newliney−(−4)=(13)(x−(−10))y - (-4) = \left(\frac{1}{3}\right)(x - (-10))
  3. Simplify Equation: Simplify the equation.\newlineSimplify the equation by removing the parentheses and the double negative signs:\newliney+4=(13)(x+10)y + 4 = \left(\frac{1}{3}\right)(x + 10)

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