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A line has a slope of 13-\frac{1}{3} and a yy-intercept of 53\frac{5}{3}. Write its equation in slope-intercept form.

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Q. A line has a slope of 13-\frac{1}{3} and a yy-intercept of 53\frac{5}{3}. Write its equation in slope-intercept form.
  1. Slope-Intercept Form: The slope-intercept form of a line is given by the equation y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Substitute Values: Given the slope mm is 13-\frac{1}{3} and the y-intercept bb is 53\frac{5}{3}, we can substitute these values into the slope-intercept form equation.
  3. Final Equation: Substituting the given values into the equation, we get y=(13)x+(53)y = (-\frac{1}{3})x + (\frac{5}{3}).
  4. Simplify if Necessary: There is no need to simplify further as the equation is already in simplest form with integers and proper fractions.

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