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A line has a slope of 12\frac{1}{2} and a yy-intercept of 32-\frac{3}{2}. Write its equation in slope-intercept form.\newline

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Q. A line has a slope of 12\frac{1}{2} and a yy-intercept of 32-\frac{3}{2}. Write its equation in slope-intercept form.\newline
  1. Identify Linear Equation Form: Identify the slope-intercept form of a linear equation.\newlineThe slope-intercept form of a linear equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Insert Given Values: Insert the given slope and y-intercept into the slope-intercept form.\newlineWe are given the slope mm as 12\frac{1}{2} and the y-intercept bb as 32-\frac{3}{2}. Substituting these values into the slope-intercept form, we get y=(12)x+(32)y = \left(\frac{1}{2}\right)x + \left(-\frac{3}{2}\right).
  3. Simplify Equation: Simplify the equation if necessary.\newlineIn this case, the equation y=12x+(32)y = \frac{1}{2}x + \left(-\frac{3}{2}\right) is already in its simplest form, so no further simplification is needed.

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