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A line has a slope of −110-\frac{1}{10} and passes through the point (5,−2)(5,-2). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)

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Q. A line has a slope of −110-\frac{1}{10} and passes through the point (5,−2)(5,-2). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney−_____=_____(x−_____)y - \_\_\_\_\_ = \_\_\_\_\_(x - \_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=−110m = -\frac{1}{10} and the point (5,−2)(5, -2). Substituting these values into the point-slope form, we get y−(−2)=(−110)(x−5)y - (-2) = (-\frac{1}{10})(x - 5).
  3. Simplify Equation: Simplify the equation.\newlineSimplifying the left side of the equation by removing the double negative, we get y+2=(−110)(x−5)y + 2 = \left(-\frac{1}{10}\right)(x - 5). This is the equation of the line in point-slope form.

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