A hot air balloon reaches its maximum cruising height of 1,500ft above sea level. Over the next 5 minutes it descends at a constant rate to a new cruising altitude of 1,200ft above sea level. If x represents the time, in minutes, after starting the initial descent, and y represents the height, in feet, of the hot air balloon, which of the following equations best models the situation for 0≤x≤5?Choose 1 answer:(A) y=1,500−5x(B) y=1,500−60x(C) y=1,500−300x(D) y=1,500−1,200x
Q. A hot air balloon reaches its maximum cruising height of 1,500ft above sea level. Over the next 5 minutes it descends at a constant rate to a new cruising altitude of 1,200ft above sea level. If x represents the time, in minutes, after starting the initial descent, and y represents the height, in feet, of the hot air balloon, which of the following equations best models the situation for 0≤x≤5?Choose 1 answer:(A) y=1,500−5x(B) y=1,500−60x(C) y=1,500−300x(D) y=1,500−1,200x
Determine Rate of Descent: We need to determine the rate of descent of the hot air balloon. The balloon descends from 1,500ft to 1,200ft, which is a change in altitude of 1,500ft−1,200ft=300ft. This descent happens over 5 minutes.
Calculate Rate of Descent per Minute: To find the rate of descent per minute, we divide the total change in altitude by the total time taken. The rate of descent is 300ft/5minutes=60ft per minute.
Create Height Equation: Now we can create an equation that models the height of the hot air balloon over time. Since the balloon starts at 1,500ft and descends at a rate of 60ft per minute, the equation is y=1,500−60x, where y is the height in feet and x is the time in minutes.
Validate Equation for Time Interval: We need to ensure that the equation is valid for the given time interval, which is from 0 to 5 minutes. Plugging in x=0, we get y=1,500−60(0)=1,500ft, which is the initial height. Plugging in x=5, we get y=1,500−60(5)=1,500−300=1,200ft, which is the final height. The equation is valid for the given time interval.
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