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A grocery store receives a shipment of bananas. The percent of the shipment that is still suitable for sale is decreasing at a rate of 
r(t) percent of the original shipment per day (where 
t is the time in days). At 
t=2, the grocery store found 
85% of the shipment to be suitable for sale.
What does

0.85+int_(2)^(4)r(t)dt=0.6" mean? "
Choose 1 answer:
(A) Between the second and fourth day, another 
60% of the bananas became unsuitable for sale.
(B) Between the second and fourth days, 
60% of the remaining bananas became unsuitable for sale per day.
(C) As of the fourth day, 
60% of the shipment was still suitable for sale.
(D) As of the fourth day, 
60% of the bananas suitable on the second day are still suitable.

A grocery store receives a shipment of bananas. The percent of the shipment that is still suitable for sale is decreasing at a rate of r(t) r(t) percent of the original shipment per day (where t t is the time in days). At t=2 t=2 , the grocery store found 85% 85 \% of the shipment to be suitable for sale.\newlineWhat does 0.85+24r(t)dt=0.6 mean?  0.85+\int_{2}^{4} r(t) d t=0.6 \text { mean? } \newlineChoose 11 answer:\newline(A) Between the second and fourth day, another 60% 60 \% of the bananas became unsuitable for sale.\newline(B) Between the second and fourth days, 60% 60 \% of the remaining bananas became unsuitable for sale per day.\newline(C) As of the fourth day, 60% 60 \% of the shipment was still suitable for sale.\newline(D) As of the fourth day, 60% 60 \% of the bananas suitable on the second day are still suitable.

Full solution

Q. A grocery store receives a shipment of bananas. The percent of the shipment that is still suitable for sale is decreasing at a rate of r(t) r(t) percent of the original shipment per day (where t t is the time in days). At t=2 t=2 , the grocery store found 85% 85 \% of the shipment to be suitable for sale.\newlineWhat does 0.85+24r(t)dt=0.6 mean?  0.85+\int_{2}^{4} r(t) d t=0.6 \text { mean? } \newlineChoose 11 answer:\newline(A) Between the second and fourth day, another 60% 60 \% of the bananas became unsuitable for sale.\newline(B) Between the second and fourth days, 60% 60 \% of the remaining bananas became unsuitable for sale per day.\newline(C) As of the fourth day, 60% 60 \% of the shipment was still suitable for sale.\newline(D) As of the fourth day, 60% 60 \% of the bananas suitable on the second day are still suitable.
  1. Given Information: We are given that at t=2t=2, 85%85\% of the shipment is suitable for sale. The equation 0.85+24r(t)dt=0.60.85 + \int_{2}^{4}r(t)dt = 0.6 includes an integral from t=2t=2 to t=4t=4, which represents the cumulative effect of the rate of decrease in suitability over these two days. The 0.850.85 at the beginning of the equation represents the 85%85\% suitability at t=2t=2.
  2. Integral Representation: The integral 24r(t)dt\int_{2}^{4}r(t)dt represents the total percentage change in suitability from day 22 to day 44. Since r(t)r(t) is the rate of decrease per day, the integral sums up these rates over the interval from t=2t=2 to t=4t=4.
  3. Equation Interpretation: The equation is set equal to 0.60.6, which means that after adding the effect of the decrease from day 22 to day 44 to the initial suitability of 85%85\%, the resulting suitability is 60%60\%.
  4. Calculation Explanation: To interpret the equation, we need to understand that the 0.850.85 is not being added to the integral's result, but rather it is the starting value (85%85\% suitable) which is being adjusted by the integral's result. The integral's result is the total percentage decrease over the two days, which when subtracted from the initial 85%85\%, results in 60%60\% suitability.
  5. Final Conclusion: Therefore, the correct interpretation of the equation is that as of the fourth day, 60%60\% of the original shipment was still suitable for sale. This means that the answer is (C) As of the fourth day, 60%60\% of the shipment was still suitable for sale.

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