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A complex number 
z_(1) has a magnitude 
|z_(1)|=13 and an angle 
theta_(1)=315^(@).
Express 
z_(1) in rectangular form, as 
z_(1)=a+bi.
Express 
a+bi in exact terms.

z_(1)=◻

A complex number z1 z_{1} has a magnitude z1=13 \left|z_{1}\right|=13 and an angle θ1=315 \theta_{1}=315^{\circ} .\newlineExpress z1 z_{1} in rectangular form, as z1=a+bi z_{1}=a+b i .\newlineExpress a+bi a+b i in exact terms.\newlinez1= z_{1}=\square

Full solution

Q. A complex number z1 z_{1} has a magnitude z1=13 \left|z_{1}\right|=13 and an angle θ1=315 \theta_{1}=315^{\circ} .\newlineExpress z1 z_{1} in rectangular form, as z1=a+bi z_{1}=a+b i .\newlineExpress a+bi a+b i in exact terms.\newlinez1= z_{1}=\square
  1. Equations for Conversion: To convert a complex number from polar to rectangular form, we use the equations a=zcos(θ)a = |z|\cos(\theta) and b=zsin(θ)b = |z|\sin(\theta), where z|z| is the magnitude and θ\theta is the angle in radians.
  2. Convert Angle to Radians: First, we need to convert the angle from degrees to radians. The angle given is 315315 degrees. To convert degrees to radians, we multiply by π/180\pi/180. So, θ1\theta_{1} in radians is 315×(π/180)=(7π/4)315 \times (\pi/180) = (7\pi/4) radians.
  3. Find Real Part aa: Now we can find the real part aa of the complex number z1z_{1}. We have z1=13|z_{1}| = 13 and θ1=7π4\theta_{1} = \frac{7\pi}{4} radians. So, a=13cos(7π4)a = 13 \cdot \cos\left(\frac{7\pi}{4}\right).
  4. Find Imaginary Part bb: The cosine of 7π4\frac{7\pi}{4} is 22\frac{\sqrt{2}}{2}. Therefore, a=13×(22)a = 13 \times \left(\frac{\sqrt{2}}{2}\right).
  5. Simplify Expressions: Now we can find the imaginary part bb of the complex number z1z_{1}. We have z1=13|z_{1}| = 13 and θ1=7π4\theta_{1} = \frac{7\pi}{4} radians. So, b=13×sin(7π4)b = 13 \times \sin(\frac{7\pi}{4}).
  6. Final Result: The sine of 7π/47\pi/4 is 2/2-\sqrt{2}/2. Therefore, b=13×(2/2)b = 13 \times (-\sqrt{2}/2).
  7. Final Result: The sine of 7π4\frac{7\pi}{4} is 22-\frac{\sqrt{2}}{2}. Therefore, b=13×(22)b = 13 \times \left(-\frac{\sqrt{2}}{2}\right). Simplifying the expressions for aa and bb, we get a=1322a = \frac{13\sqrt{2}}{2} and b=1322b = -\frac{13\sqrt{2}}{2}.
  8. Final Result: The sine of 7π/47\pi/4 is 2/2-\sqrt{2}/2. Therefore, b=13×(2/2)b = 13 \times (-\sqrt{2}/2). Simplifying the expressions for aa and bb, we get a=132/2a = 13\sqrt{2}/2 and b=132/2b = -13\sqrt{2}/2. Therefore, the complex number z1z_{1} in rectangular form is z1=132/2132/2×iz_{1} = 13\sqrt{2}/2 - 13\sqrt{2}/2 \times i.

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