Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A committee must be formed with 5 teachers and 5 students. If there are 9 teachers to choose from, and 14 students, how many different ways could the committee be made?
Answer:

A committee must be formed with 55 teachers and 55 students. If there are 99 teachers to choose from, and 1414 students, how many different ways could the committee be made?\newlineAnswer:

Full solution

Q. A committee must be formed with 55 teachers and 55 students. If there are 99 teachers to choose from, and 1414 students, how many different ways could the committee be made?\newlineAnswer:
  1. Calculate Combinations for Teachers: To determine the number of different ways to form the committee, we need to calculate the combinations of teachers and students separately and then multiply them together. For the teachers, we will use the combination formula which is C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n - k)!}, where nn is the total number of items to choose from, kk is the number of items to choose, and !"!" denotes factorial.
  2. Calculate Combinations for Students: First, we calculate the number of ways to choose 55 teachers out of 99. Using the combination formula:\newlineC(9,5)=9!5!(95)!=9!5!4!=9×8×7×6×5!5!×4×3×2×1=9×8×7×64×3×2×1=126C(9, 5) = \frac{9!}{5!(9 - 5)!} = \frac{9!}{5!4!} = \frac{9\times8\times7\times6\times5!}{5!\times4\times3\times2\times1} = \frac{9\times8\times7\times6}{4\times3\times2\times1} = 126
  3. Multiply Combinations: Next, we calculate the number of ways to choose 55 students out of 1414. Using the combination formula again:\newlineC(14,5)=14!(5!(145)!)=14!(5!9!)=(14×13×12×11×10×9!)(5!×9!)=(14×13×12×11×10)(5×4×3×2×1)=2002C(14, 5) = \frac{14!}{(5!(14 - 5)!)} = \frac{14!}{(5!9!)} = \frac{(14\times13\times12\times11\times10\times9!)}{(5!\times9!)} = \frac{(14\times13\times12\times11\times10)}{(5\times4\times3\times2\times1)} = 2002
  4. Calculate Total Ways: Now, we multiply the number of combinations of teachers by the number of combinations of students to find the total number of ways to form the committee: Total number of ways = Number of ways to choose teachers ×\times Number of ways to choose students = 126×2002126 \times 2002
  5. Perform Multiplication: Perform the multiplication to find the total number of ways:\newlineTotal number of ways = 126×2002=252252126 \times 2002 = 252252

More problems from Counting principle