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A chalkboard has a perimeter of 16feet16\,\text{feet}. Its area is 15square feet15\,\text{square feet}. What are the dimensions of the board?\newline____\_\_\_\_ feet by ____\_\_\_\_ feet

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Q. A chalkboard has a perimeter of 16feet16\,\text{feet}. Its area is 15square feet15\,\text{square feet}. What are the dimensions of the board?\newline____\_\_\_\_ feet by ____\_\_\_\_ feet
  1. Define Variables: Let ll be the length and ww be the width of the chalkboard.\newlineThe perimeter of a rectangle is given by the formula P=2l+2wP = 2l + 2w.
  2. Perimeter Equation: Given the perimeter of the chalkboard is 1616 feet, we can write the equation 16=2l+2w16 = 2l + 2w.
  3. Simplify Perimeter: Simplify the perimeter equation by dividing all terms by 22 to get 8=l+w8 = l + w.
  4. Area Equation: The area of a rectangle is given by the formula A=lwA = lw.\newlineGiven the area of the chalkboard is 1515 square feet, we can write the equation 15=lw15 = lw.
  5. Solve System: We now have a system of two equations with two variables:\newline11. 8=l+w8 = l + w\newline22. 15=lw15 = lw\newlineWe can solve this system by expressing one variable in terms of the other using the first equation and then substituting into the second equation.
  6. Express ww in terms of ll: From the first equation, express ww in terms of ll: w=8lw = 8 - l.
  7. Substitute into Area Equation: Substitute w=8lw = 8 - l into the second equation 15=lw15 = lw to get 15=l(8l)15 = l(8 - l).
  8. Expand Equation: Expand the equation 15=l(8l)15 = l(8 - l) to get 15=8ll215 = 8l - l^2.
  9. Form Quadratic Equation: Rearrange the equation to form a quadratic equation: l28l+15=0l^2 - 8l + 15 = 0.
  10. Factor Quadratic Equation: Factor the quadratic equation to find the values of ll: (l3)(l5)=0(l - 3)(l - 5) = 0.
  11. Solve for ll: Set each factor equal to zero and solve for ll: l3=0l - 3 = 0 or l5=0l - 5 = 0. This gives us l=3l = 3 or l=5l = 5.
  12. Find Dimensions: If l=3l = 3, then w=8l=83=5w = 8 - l = 8 - 3 = 5. If l=5l = 5, then w=8l=85=3w = 8 - l = 8 - 5 = 3. So the dimensions of the chalkboard can be either 33 feet by 55 feet or 55 feet by 33 feet.

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