Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A body constrained to move along the 
z-axis of a coordinate system is subject to a constant force 
F given by 
F=- hat(i)+2 hat(j)+3 hat(k)N. Where 
hat(i), hat(j), hat(k) are unit vectors along the 
x,y and 
z axis of the system respectively. What is the work done by this force in moving the body a distance of 
4m along the 
z axis?

A body constrained to move along the z z -axis of a coordinate system is subject to a constant force F F given by F=i^+2j^+3k^N F=-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}} N . Where i^,j^,k^ \hat{\mathbf{i}}, \hat{\mathbf{j}}, \hat{\mathbf{k}} are unit vectors along the x,y x, y and z z axis of the system respectively. What is the work done by this force in moving the body a distance of 4 m 4 \mathrm{~m} along the z \mathrm{z} axis?

Full solution

Q. A body constrained to move along the z z -axis of a coordinate system is subject to a constant force F F given by F=i^+2j^+3k^N F=-\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}} N . Where i^,j^,k^ \hat{\mathbf{i}}, \hat{\mathbf{j}}, \hat{\mathbf{k}} are unit vectors along the x,y x, y and z z axis of the system respectively. What is the work done by this force in moving the body a distance of 4 m 4 \mathrm{~m} along the z \mathrm{z} axis?
  1. Understand Work Done Definition: Understand the concept of work done by a force. Work done by a force is defined as the dot product of the force vector and the displacement vector. The formula for work done WW is: W=FdW = \mathbf{F} \cdot \mathbf{d} where F\mathbf{F} is the force vector, d\mathbf{d} is the displacement vector, and \cdot represents the dot product.
  2. Identify Force and Displacement: Identify the components of the force vector and the displacement vector.\newlineThe force vector F\mathbf{F} is given by F=i^+2j^+3k^\mathbf{F} = - \hat{i} + 2 \hat{j} + 3 \hat{k} N.\newlineThe displacement vector d\mathbf{d} along the z-axis is d=4k^\mathbf{d} = 4 \hat{k} m, since the body moves 44 meters along the z-axis and there is no movement along the x or y axes.
  3. Calculate Dot Product: Calculate the dot product of the force vector and the displacement vector.\newlineThe dot product of two vectors is calculated by multiplying their corresponding components and then summing those products. Since the displacement is only along the z-axis, only the z-component of the force will do work.\newlineW=Fd=(i^+2j^+3k^)(0i^+0j^+4k^)W = \mathbf{F} \cdot \mathbf{d} = (- \hat{i} + 2 \hat{j} + 3 \hat{k}) \cdot (0 \hat{i} + 0 \hat{j} + 4 \hat{k})\newlineW=(0×1)+(0×2)+(3×4)W = (0 \times -1) + (0 \times 2) + (3 \times 4)
  4. Find Work Done: Perform the multiplication and addition to find the work done.\newlineW=0+0+12W = 0 + 0 + 12\newlineW=12W = 12 Joules

More problems from Relate position, velocity, speed, and acceleration using derivatives