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A bedroom door has a perimeter of 2828 feet and an area of 4040 square feet. What are the dimensions of the door?\newline___\_\_\_ feet by ___\_\_\_ feet

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Q. A bedroom door has a perimeter of 2828 feet and an area of 4040 square feet. What are the dimensions of the door?\newline___\_\_\_ feet by ___\_\_\_ feet
  1. Perimeter Equation: Let's denote the length of the door as ll and the width as ww. The perimeter of a rectangle is given by the formula P=2l+2wP = 2l + 2w. Since we know the perimeter is 2828 feet, we can write the equation 2l+2w=282l + 2w = 28.
  2. Simplify Perimeter Equation: To simplify the equation, we can divide both sides by 22, which gives us l+w=14l + w = 14.
  3. Area Equation: The area of a rectangle is given by the formula A=lwA = lw. We know the area is 4040 square feet, so we can write the equation lw=40lw = 40.
  4. Solve System of Equations: We now have a system of two equations with two variables:\newline11. l+w=14l + w = 14\newline22. lw=40lw = 40\newlineWe can solve this system by expressing one variable in terms of the other using the first equation. Let's solve for ww: w=14lw = 14 - l.
  5. Substitute Width: Substitute ww from the previous step into the area equation: l(14l)=40l(14 - l) = 40.
  6. Expand Equation: Expand the equation: 14ll2=4014l - l^2 = 40.
  7. Rearrange Equation: Rearrange the equation to form a quadratic equation: l214l+40=0l^2 - 14l + 40 = 0.
  8. Factor Quadratic Equation: Factor the quadratic equation: l - \(10)(l - 44) = 00\
  9. Solve for Length: Set each factor equal to zero and solve for ll: l10=0l - 10 = 0 or l4=0l - 4 = 0, which gives us l=10l = 10 or l=4l = 4.
  10. Possible Dimensions: Since ll and ww are interchangeable in a rectangle (one can be the length and the other the width), we have two possible dimensions for the door: 1010 feet by 44 feet or 44 feet by 1010 feet.

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