Which polynomials are in standard form? Choose all answers that apply: A 3z-1 B 2+4x-5x^(2) C -5p^(5)+2p^(2)-3p+1 D None of the above

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Which polynomials are in standard form? Choose all answers that apply: A  3z-1 B  2+4x-5x^(2) C  -5p^(5)+2p^(2)-3p+1 D None of the above

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Identify Standard Form: A polynomial is in standard form when its terms are ordered from highest to lowest degree. Let's check each option.Check Option A: Option A: 3z - 1 This polynomial has two terms. The first term is 3z (which is of degree 1 since z is to the power of 1), and the second term is -1 (which is a constant term or of degree 0). Since the terms are ordered from the highest degree to the lowest, this polynomial is in standard form.Check Option B: Option B: 2 + 4x - 5x^2 This polynomial has three terms. The terms are not ordered correctly; they should be arranged from the highest degree to the lowest. The correct order should be -5x^2 (degree 2), 4x (degree 1), and then 2 (degree 0). Since it is not in this order, this polynomial is not in standard form.Check Option C: Option C: -5p^5 + 2p^2 - 3p + 1 This polynomial has four terms. The terms are ordered from the highest degree to the lowest: -5p^5 (degree 5), 2p^2 (degree 2), -3p (degree 1), and 1 (degree 0). This polynomial is in standard form.Eliminate Option D: Option D: None of the above Since we have found that options A and C are in standard form, option D is not a correct answer.

Which polynomials are in standard form? $\newline$ Choose all answers that apply: $\newline$ A $3 z-1$ $\newline$ B $2+4 x-5 x^{2}$ $\newline$ C $-5 p^{5}+2 p^{2}-3 p+1$ $\newline$ D None of the above

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Which polynomials are in standard form?\newlineChoose all answers that apply:\newlineA 3z−1 3 z-1 3z−1\newlineB 2+4x−5x2 2+4 x-5 x^{2} 2+4x−5x2\newlineC −5p5+2p2−3p+1 -5 p^{5}+2 p^{2}-3 p+1 −5p5+2p2−3p+1\newlineD None of the above

Which polynomials are in standard form? $\newline$ Choose all answers that apply: $\newline$ A $3 z-1$ $\newline$ B $2+4 x-5 x^{2}$ $\newline$ C $-5 p^{5}+2 p^{2}-3 p+1$ $\newline$ D None of the above