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Which ordered pair is a solution of the equation?

y+5=2(x+1)
Choose 1 answer:
(A) 
Only(5,10)
(B) Only 
(-1,-5)
(c) Both 
(5,10) and 
(-1,-5)
(D) Neither

Which ordered pair is a solution of the equation?\newliney+5=2(x+1) y+5=2(x+1) \newlineChoose 11 answer:\newline(A) Only (5,10) (5,10) \newline(B) Only (1,5) (-1,-5) \newline(C) Both (5,10) (5,10) and (1,5) (-1,-5) \newline(D) Neither

Full solution

Q. Which ordered pair is a solution of the equation?\newliney+5=2(x+1) y+5=2(x+1) \newlineChoose 11 answer:\newline(A) Only (5,10) (5,10) \newline(B) Only (1,5) (-1,-5) \newline(C) Both (5,10) (5,10) and (1,5) (-1,-5) \newline(D) Neither
  1. Understanding the equation: Understand the equation in question.\newlineThe equation given is y+5=2(x+1)y + 5 = 2(x + 1). This is a linear equation in two variables, xx and yy.
  2. Simplifying the equation: Simplify the equation.\newlineTo find the solution, we need to simplify the equation to its standard form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.\newliney+5=2(x+1)y + 5 = 2(x + 1)\newliney+5=2x+2y + 5 = 2x + 2\newliney=2x+25y = 2x + 2 - 5\newliney=2x3y = 2x - 3
  3. Testing the ordered pair (5,10)(5, 10): Test the ordered pair (5,10)(5, 10).\newlineSubstitute x=5x = 5 and y=10y = 10 into the simplified equation to check if it satisfies the equation.\newline10=2(5)310 = 2(5) - 3\newline10=10310 = 10 - 3\newline10710 \neq 7\newlineThe ordered pair (5,10)(5, 10) does not satisfy the equation.
  4. Testing the ordered pair (1,5)(-1, -5): Test the ordered pair (1,5)(-1, -5).\newlineSubstitute x=1x = -1 and y=5y = -5 into the simplified equation to check if it satisfies the equation.\newline5=2(1)3-5 = 2(-1) - 3\newline5=23-5 = -2 - 3\newline5=5-5 = -5\newlineThe ordered pair (1,5)(-1, -5) satisfies the equation.
  5. Determining the correct answer: Determine the correct answer based on the tests.\newlineSince the ordered pair (1,5)(-1, -5) satisfies the equation and the ordered pair (5,10)(5, 10) does not, the correct answer is (B) Only (1,5)(-1, -5).

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