Which ordered pair is a solution of the equation? y+1=3(x-4) Choose 1 answer: (A) Only (4,-1) (B) Only(5,2) (c) Both (4,-1) and (5,2) (D) Neither

Equation Understanding: Understand the equation in question. The equation given is y + 1 = 3(x - 4). This is a linear equation in two variables, x and y.Validity Check for Option (A): Substitute the x and y values from option (A) into the equation to check for validity. For the ordered pair (4, -1), substitute x = 4 and y = -1 into the equation and see if the equation holds true. y + 1 = 3(x - 4) -1 + 1 = 3(4 - 4) 0 = 3(0) 0 = 0Validity Check for Option (B): Since the equation holds true for the ordered pair (4, -1), option (A) is a valid solution.Final Answer Determination: Substitute the x and y values from option (B) into the equation to check for validity. For the ordered pair (5, 2), substitute x = 5 and y = 2 into the equation and see if the equation holds true. y + 1 = 3(x - 4) 2 + 1 = 3(5 - 4) 3 = 3(1) 3 = 3Since the equation holds true for the ordered pair (5, 2), option (B) is also a valid solution.Determine the final answer based on the validity of options (A) and (B). Since both ordered pairs (4, -1) and (5, 2) satisfy the equation, the correct answer is (C) Both (4, -1) and (5, 2).

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Which ordered pair is a solution of the equation?

y+1=3(x-4)
Choose 1 answer:
(A) Only
(4,-1)
(B)
Only(5,2)
(c) Both
(4,-1) and
(5,2)
(D) Neither

Which ordered pair is a solution of the equation? $\newline$ $y+1=3(x-4)$ $\newline$ Choose $1$ answer: $\newline$ (A) Only $(4,-1)$ $\newline$ (B) Only $(5,2)$ $\newline$ (C) Both $(4,-1)$ and $(5,2)$ $\newline$ (D) Neither

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Algebra 1

Does (x, y) satisfy the linear equation?

Full solution

Q. Which ordered pair is a solution of the equation?

\newline

y+1=3(x-4)

\newline

Choose

1

answer:

\newline

(A) Only

(4,-1)

\newline

(B) Only

(5,2)

\newline

(4,-1)

and

(5,2)

\newline

(D) Neither

Equation Understanding: Understand the equation in question. $\newline$ The equation given is $y + 1 = 3(x - 4)$ . This is a linear equation in two variables, $x$ and $y$ .
Validity Check for Option (A): Substitute the $x$ and $y$ values from option (A) into the equation to check for validity. $\newline$ For the ordered pair $(4, -1)$ , substitute $x = 4$ and $y = -1$ into the equation and see if the equation holds true. $\newline$ $y + 1 = 3(x - 4)$ $\newline$ $-1 + 1 = 3(4 - 4)$ $\newline$ $0 = 3(0)$ $\newline$ $0 = 0$
Validity Check for Option (B): Since the equation holds true for the ordered pair $(4, -1)$ , option (A) is a valid solution.
Final Answer Determination: Substitute the $x$ and $y$ values from option (B) into the equation to check for validity. $\newline$ For the ordered pair $(5, 2)$ , substitute $x = 5$ and $y = 2$ into the equation and see if the equation holds true. $\newline$ $y + 1 = 3(x - 4)$ $\newline$ $2 + 1 = 3(5 - 4)$ $\newline$ $3 = 3(1)$ $\newline$ $3 = 3$
Final Answer Determination: Substitute the $x$ and $y$ values from option (B) into the equation to check for validity. $\newline$ For the ordered pair $(5, 2)$ , substitute $x = 5$ and $y = 2$ into the equation and see if the equation holds true. $\newline$ $y + 1 = 3(x - 4)$ $\newline$ $2 + 1 = 3(5 - 4)$ $\newline$ $3 = 3(1)$ $\newline$ $3 = 3$ Since the equation holds true for the ordered pair $(5, 2)$ , option (B) is also a valid solution.
Final Answer Determination: Substitute the $x$ and $y$ values from option (B) into the equation to check for validity. $\newline$ For the ordered pair $(5, 2)$ , substitute $x = 5$ and $y = 2$ into the equation and see if the equation holds true. $\newline$ $y + 1 = 3(x - 4)$ $\newline$ $2 + 1 = 3(5 - 4)$ $\newline$ $3 = 3(1)$ $\newline$ $3 = 3$ Since the equation holds true for the ordered pair $(5, 2)$ , option (B) is also a valid solution.Determine the final answer based on the validity of options (A) and (B). $\newline$ Since both ordered pairs $y$ $0$ and $(5, 2)$ satisfy the equation, the correct answer is (C) Both $y$ $0$ and $(5, 2)$ .