Q. Which ordered pair is a solution of the equation?6x+3y=15Choose 1 answer:(A) Only (3,−2)(B) Only (2,2)(C) Both (3,−2) and (2,2)(D) Neither
Check (3,−2): Substitute the x and y values from option (A) into the equation to check if it satisfies the equation.For (3,−2), substitute x=3 and y=−2 into the equation 6x+3y=15.Calculation: 6(3)+3(−2)=18−6=12.Check if the result equals 15.
Check (2,2): Since 12 does not equal 15, (3,−2) is not a solution to the equation.
Neither satisfies the equation: Substitute the and values from option (B) into the equation to check if it satisfies the equation.For , substitute x = 222 and y = 222 into the equation 666x + 333y = 151515.\newlineCalculation: 666(222) + 333(222) = 121212 + 666 = 181818.\newlineCheck if the result equals 151515.
Neither satisfies the equation: Substitute the xxx and yyy values from option (B) into the equation to check if it satisfies the equation.\newlineFor (2,2)(2, 2)(2,2), substitute x=2x = 2x=2 and y=2y = 2y=2 into the equation 6x+3y=156x + 3y = 156x+3y=15.\newlineCalculation: 6(2)+3(2)=12+6=186(2) + 3(2) = 12 + 6 = 186(2)+3(2)=12+6=18.\newlineCheck if the result equals 151515.Since 181818 does not equal 151515, (2,2)(2, 2)(2,2) is not a solution to the equation.
Neither satisfies the equation: Substitute the xxx and yyy values from option (B) into the equation to check if it satisfies the equation.\newlineFor (2,2)(2, 2)(2,2), substitute x=2x = 2x=2 and y=2y = 2y=2 into the equation 6x+3y=156x + 3y = 156x+3y=15.\newlineCalculation: 6(2)+3(2)=12+6=186(2) + 3(2) = 12 + 6 = 186(2)+3(2)=12+6=18.\newlineCheck if the result equals 151515.Since 181818 does not equal 151515, (2,2)(2, 2)(2,2) is not a solution to the equation.Since neither yyy111 nor (2,2)(2, 2)(2,2) satisfy the equation, the correct answer is (D) Neither.
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