Which of the following is an equation of the line in the xy-plane that passes through the point (3,−4) and is perpendicular to the line with equation y=41x−7 ?Choose 1 answer:(A) y=41x+8(B) y=41x−8(C) y=−4x+8(D) y=−4x−8
Q. Which of the following is an equation of the line in the xy-plane that passes through the point (3,−4) and is perpendicular to the line with equation y=41x−7 ?Choose 1 answer:(A) y=41x+8(B) y=41x−8(C) y=−4x+8(D) y=−4x−8
Finding the slope of the given line: The slope of the given line is the coefficient of x in the equation y=41x−7, which is 41.
Determining the slope of the perpendicular line: Since the line we are looking for is perpendicular to the given line, its slope will be the negative reciprocal of 41. The negative reciprocal of 41 is −4.
Using the point-slope form to find the equation: Now we have the slope of the new line, which is −4, and a point it passes through, which is (3,−4). We can use the point-slope form of the equation of a line to find the equation of our line. The point-slope form is y−y1=m(x−x1), where m is the slope and (x1,y1) is the point the line passes through.
Simplifying the equation: Plugging the slope and the point into the point-slope form, we get y−(−4)=−4(x−3). Simplifying this, we get y+4=−4x+12.
Converting to slope-intercept form: Subtracting 4 from both sides of the equation to get it into slope-intercept form (y=mx+b), we get y=−4x+12−4, which simplifies to y=−4x+8.
Matching the equation with the options: Comparing the equation y=−4x+8 with the answer choices, we find that it matches with option (C).
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