When an Alvia high-speed train that is stopped in Barcelona leaves the station, its speed increases (accelerates) at a constant rate of 3,888 kilometers per hour squared ((km)/(hr^(2))). If h is the time, in hours, it takes for the train to reach a speed of 250(km)/(hr), which of the following equations best describes this situation? Choose 1 answer: (A) 250=(3,888)/(60)h (B) 250=3,888 h (C) 3,888=250 h (D) 250=3,888(60)h

Given Information: We are given that the train accelerates at a constant rate of 3,888 kilometers per hour squared. The formula for acceleration is final speed (v) equals initial speed (u) plus acceleration (a) times time (t). Since the train starts from rest, the initial speed u is 0. Therefore, the formula simplifies to v = at. We need to find the time h it takes for the train to reach a speed of 250 km/hr.Acceleration Formula: Substitute the given values into the simplified acceleration formula. We have v = 250 km/hr and a = 3,888 km/hr^2. So, we get 250 = 3,888 * h.Substitute Values: To find h, we need to divide both sides of the equation by the acceleration 3,888 km/hr^2. This gives us h = 250 / 3,888.Calculate Time: However, we need to check the answer choices to see which one matches our equation. Choice (A) has a division by 60, which is not part of our calculation. Choice (B) matches our equation exactly. Choice (C) has the variables switched, and choice (D) has an unnecessary multiplication by 60. Therefore, the correct answer is (B) 250 = 3,888 h.

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When an Alvia high-speed train that is stopped in Barcelona leaves the station, its speed increases (accelerates) at a constant rate of $3$ , $888$ kilometers per hour squared $\left(\frac{\mathrm{km}}{\mathrm{hr}^{2}}\right)$ . If $h$ is the time, in hours, it takes for the train to reach a speed of $250 \frac{\mathrm{km}}{\mathrm{hr}}$ , which of the following equations best describes this situation? $\newline$ Choose $1$ answer: $\newline$ (A) $250=\frac{3,888}{60} h$ $\newline$ (B) $250=3,888 h$ $\newline$ (C) $3,888=250 h$ $\newline$ (D) $250=3,888(60) h$

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Q. When an Alvia high-speed train that is stopped in Barcelona leaves the station, its speed increases (accelerates) at a constant rate of

3

888

kilometers per hour squared

\left(\frac{\mathrm{km}}{\mathrm{hr}^{2}}\right)

. If

h

is the time, in hours, it takes for the train to reach a speed of

250 \frac{\mathrm{km}}{\mathrm{hr}}

, which of the following equations best describes this situation?

\newline

Choose

1

answer:

\newline

(A)

250=\frac{3,888}{60} h

\newline

(B)

250=3,888 h

\newline

(C)

3,888=250 h

\newline

(D)

250=3,888(60) h

Given Information: We are given that the train accelerates at a constant rate of $3,888 \, \text{kilometers per hour squared}$ . The formula for acceleration is final speed $(v)$ equals initial speed $(u)$ plus acceleration $(a)$ times time $(t)$ . Since the train starts from rest, the initial speed $u$ is $0$ . Therefore, the formula simplifies to $v = at$ . We need to find the time $h$ it takes for the train to reach a speed of $250 \, \text{km/hr}$ .
Acceleration Formula: Substitute the given values into the simplified acceleration formula. We have $v = 250 \, \text{km/hr}$ and $a = 3,888 \, \text{km/hr}^2$ . So, we get $250 = 3,888 \times h$ .
Substitute Values: To find $h$ , we need to divide both sides of the equation by the acceleration $3,888 \, \text{km/hr}^2$ . This gives us $h = \frac{250}{3,888}.$
Calculate Time: However, we need to check the answer choices to see which one matches our equation. Choice (A) has a division by $60$ , which is not part of our calculation. Choice (B) matches our equation exactly. Choice (C) has the variables switched, and choice (D) has an unnecessary multiplication by $60$ . Therefore, the correct answer is (B) $250 = 3,888 \, h$ .