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What is 
y-8=3(x+1) written in standard form?
Choose 1 answer:
(A) 
-3x+y=11
(B) 
y-8=3x+3
(C) 
y=3x+11
(D) 
-3x+y-11=0

What is y8=3(x+1) y-8=3(x+1) written in standard form?\newlineChoose 11 answer:\newline(A) 3x+y=11 -3 x+y=11 \newline(B) y8=3x+3 y-8=3 x+3 \newline(C) y=3x+11 y=3 x+11 \newline(D) 3x+y11=0 -3 x+y-11=0

Full solution

Q. What is y8=3(x+1) y-8=3(x+1) written in standard form?\newlineChoose 11 answer:\newline(A) 3x+y=11 -3 x+y=11 \newline(B) y8=3x+3 y-8=3 x+3 \newline(C) y=3x+11 y=3 x+11 \newline(D) 3x+y11=0 -3 x+y-11=0
  1. Distribute the 33: First, distribute the 33 to the terms inside the parentheses.y8=3(x+1)y - 8 = 3(x + 1)y8=3x+3y - 8 = 3x + 3
  2. Add 88 to both sides: Next, add 88 to both sides of the equation to move the constant term to the right side.\newliney8+8=3x+3+8y - 8 + 8 = 3x + 3 + 8\newliney=3x+11y = 3x + 11
  3. Rearrange terms to standard form: Now, we need to rearrange the terms to get the equation in standard form, which is Ax+By=CAx + By = C. We want the xx term first, followed by the yy term, and then the constant.\newline3x+y=11-3x + y = 11
  4. Check answer choices: Finally, we check the answer choices to see which one matches our equation in standard form.\newline(A)3x+y=11(A) -3x + y = 11 is the correct standard form of the given equation.

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