What is the x-intercept of the graph of y=(x-5)^(2) ? Choose 1 answer: (A) -25 (B) -5 (c) 5 (D) 25

Set y equal to 0: To find the x-intercept of the graph, we need to set y equal to 0 and solve for x. 0 = (x-5)^(2)Take the square root: Now we need to find the value of x that makes the equation true. Since we have a square, we can take the square root of both sides of the equation. √0 = √(x-5)^(2)Simplify the equation: The square root of 0 is 0, and the square root of (x-5)^(2) is x-5 (since the square root and the square are inverse operations). 0 = x - 5Solve for x: Now we solve for x by adding 5 to both sides of the equation. x = 5

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What is the
x-intercept of the graph of
y=(x-5)^(2) ?
Choose 1 answer:
(A) -25
(B) -5
(c) 5
(D) 25

What is the $x$ -intercept of the graph of $y=(x-5)^{2}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $-25$ $\newline$ (B) $-5$ $\newline$ (C) $5$ $\newline$ (D) $25$

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Math Problems

Algebra 2

Evaluate exponential functions

Full solution

Q. What is the

x

-intercept of the graph of

y=(x-5)^{2}

\newline

Choose

1

answer:

\newline

(A)

-25

\newline

(B)

-5

\newline

(C)

5

\newline

(D)

25

Set $y$ equal to $0$ : To find the x-intercept of the graph, we need to set $y$ equal to $0$ and solve for $x$ . $0 = (x-5)^{2}$
Take the square root: Now we need to find the value of $x$ that makes the equation true. Since we have a square, we can take the square root of both sides of the equation. $\newline$ $\sqrt{0} = \sqrt{(x-5)^{2}}$
Simplify the equation: The square root of $0$ is $0$ , and the square root of $(x-5)^{2}$ is $x-5$ (since the square root and the square are inverse operations). $\newline$ $0 = x - 5$
Solve for x: Now we solve for x by adding $5$ to both sides of the equation. $\newline$ $x = 5$