Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the value of 
cos(60^(@)) ?

What is the value of cos(60)? \cos \left(60^{\circ}\right) ?

Full solution

Q. What is the value of cos(60)? \cos \left(60^{\circ}\right) ?
  1. Recognizing 6060^\circ as a special angle: Recognize that 6060^\circ is a special angle in trigonometry, and we can use the unit circle or special triangles to find the cosine of this angle.
  2. Using special triangles to find cosine of 6060 degrees: Recall that the cosine of 6060 degrees corresponds to the adjacent side over the hypotenuse in a 3030-6060-9090 special right triangle, where the sides are in the ratio 1:3:21:\sqrt{3}:2.
  3. Calculating cosine of 6060 degrees using special triangle ratio: In such a triangle, the cosine of 6060 degrees is equal to the length of the shorter leg (adjacent to the 6060-degree angle) over the hypotenuse. The shorter leg has a length of 11, and the hypotenuse has a length of 22.
  4. Calculating cosine of 6060 degrees using special triangle ratio: In such a triangle, the cosine of 6060 degrees is equal to the length of the shorter leg (adjacent to the 6060-degree angle) over the hypotenuse. The shorter leg has a length of 11, and the hypotenuse has a length of 22.Calculate the value of cos(60)\cos(60^\circ) using the ratio from the special triangle: cos(60)=12\cos(60^\circ) = \frac{1}{2}.

More problems from Relationship between squares and square roots