What is the inverse of the function f(x)=8x+1 ? f^(-1)(x)=

Replace with y: To find the inverse of the function f(x) = 8x + 1, we first replace f(x) with y. So, we have y = 8x + 1.Swap x and y: Next, we swap x and y to get the inverse function. This gives us x = 8y + 1.Solve for y: Now, we solve for y to get the inverse function f^(-1)(x). We start by subtracting 1 from both sides of the equation. x - 1 = 8y + 1 - 1 x - 1 = 8yDivide by 8: Finally, we divide both sides of the equation by 8 to solve for y. (x - 1) / 8 = 8y / 8 y = (x - 1) / 8Inverse function: We have found the inverse function. So, f^(-1)(x) = (x - 1) / 8.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the inverse of the function
f(x)=8x+1 ?

f^(-1)(x)=

What is the inverse of the function $\newline$ $f(x)=8x+1$ ? $\newline$ $f^{-1}(x)=$

View step-by-step help

Home

Math Problems

Algebra 2

Evaluate exponential functions

Full solution

Q. What is the inverse of the function

\newline

f(x)=8x+1

\newline

f^{-1}(x)=

Replace with y: To find the inverse of the function $f(x) = 8x + 1$ , we first replace $f(x)$ with $y$ . $\newline$ So, we have $y = 8x + 1$ .
Swap $x$ and $y$ : Next, we swap $x$ and $y$ to get the inverse function. This gives us $x = 8y + 1$ .
Solve for y: Now, we solve for y to get the inverse function $f^{-1}(x)$ . We start by subtracting $1$ from both sides of the equation. $\newline$ $x - 1 = 8y + 1 - 1$ $\newline$ $x - 1 = 8y$
Divide by $8$ : Finally, we divide both sides of the equation by $8$ to solve for $y$ . $\frac{x - 1}{8} = \frac{8y}{8}$ $y = \frac{x - 1}{8}$
Inverse function: We have found the inverse function. So, $f^{-1}(x) = \frac{x - 1}{8}.$